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340=6x^2
We move all terms to the left:
340-(6x^2)=0
a = -6; b = 0; c = +340;
Δ = b2-4ac
Δ = 02-4·(-6)·340
Δ = 8160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8160}=\sqrt{16*510}=\sqrt{16}*\sqrt{510}=4\sqrt{510}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{510}}{2*-6}=\frac{0-4\sqrt{510}}{-12} =-\frac{4\sqrt{510}}{-12} =-\frac{\sqrt{510}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{510}}{2*-6}=\frac{0+4\sqrt{510}}{-12} =\frac{4\sqrt{510}}{-12} =\frac{\sqrt{510}}{-3} $
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